using System; using L=Science.Physics.GeneralPhysics; namespace Serway.Chapter25 { /// /// Example03: The Electric Potential Due to Two Point Charges. /// A charge q_1 = 2.00 \mu C is located at the origin, and /// a charge q_2 = -6.00 \mu C is located at (0,3.00)m, as shown /// in Figure 25.12a. /// (A) /// Find the total electric potential due to these charges /// at the point P, whose coordinates are (4.00, 0) m. /// V_P = -6.29 \times 10^3 V /// (B) /// Find the change in potential energy of the system of /// two charges plus a charge q_3 = 3.00 \mu C as the latter charge /// moves from infinity to point P (Fig.25.12b) /// \Delta U = -1.89 \times 10^{-2} J /// public class Example03 { public Example03() { } private string result; public string Result { get{return result;} } public void Compute() { L.ElectricCharge q1 = new L.ElectricCharge(); q1.C = 2.0E-6; L.Position A = new L.Position(); A.X = 0.0; A.Y = 0.0; A.Z = 0.0; L.ElectricCharge q2 = new L.ElectricCharge(); q2.C = -6.0E-6; L.Position B = new L.Position(); B.X = 0.0; B.Y = 3.0; B.Z = 0.0; L.Position P = new L.Position(); P.X = 4.0; P.Y = 0.0; P.Z = 0.0; L.ElectricPotential V1 = new L.ElectricPotential(q1,A,P); L.ElectricPotential V2 = new L.ElectricPotential(q2,B,P); L.ElectricPotential VP = new L.ElectricPotential(); VP.V = V1.V + V2.V; //(A) result+=VP.ToString()+"\r\n"; //(B) L.ElectricCharge q3 = new L.ElectricCharge(); q3.C = 3.0E-6; L.PotentialEnergy U = new L.PotentialEnergy(q3,VP); result+=U.ToString()+"\r\n"; } } } //-6291.25 +/- 0 (V) //-0.01887375 +/- 0 (J)