using System; using L=Science.Physics.GeneralPhysics; namespace Serway.Chapter27 { /// /// Example02: The Resistance of a Conductor /// Calculate the resistance of an aluminum cylinder that has /// a length of 10.0 cm and a cross-sectional area of /// 2 \times 10^{-4} m^2. Repeat the calculation for a cylinder /// of the same dimensions and made of glass having /// a resistivity of 3.0 \times 10^{10} \Omega m. /// public class Example02 { public Example02() { } private string result; public string Result { get{return result;} } public void Compute() { L.Length l = new L.Length(); l.m = 0.1; L.Area A = new L.Area(); A.mSQUARE = 2.0E-4; //(A) L.Resistivity rho = new L.Resistivity(); rho.Ohmm = 2.82E-8; L.Resistance R = new L.Resistance(rho,l,A); result+=R.ToString()+" "; //(B) L.Resistivity rhop = new L.Resistivity(); rhop.Ohmm = 3.0E10; L.Resistance Rp = new L.Resistance(rhop,l,A); result+=Rp.ToString(); } } } //1.41E-05 +/- 0 (Ohm) 15000000000000 +/- 0 (Ohm)